x+x^2=20.3125

Solution for x+x^2=20.3125 equation:

x+x^2=20.3125

We move all terms to the left:

x+x^2-(20.3125)=0

We add all the numbers together, and all the variables

x^2+x-20.3125=0

a = 1; b = 1; c = -20.3125;
Δ = b2-4ac
Δ = 12-4·1·(-20.3125)
Δ = 82.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{82.25}}{2*1}=\frac{-1-\sqrt{82.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{82.25}}{2*1}=\frac{-1+\sqrt{82.25}}{2}
$